S = {1,2,3,4,5,6}

N(S) = 6

A = {3,5)

N(A) = 2

P(A) = $\frac{N\left(A\right)}{N\left(S\right)}=\frac{2}{6}=\frac{1}{3}$

Fh = P(A) x n

Keterangan Rumus:

Fh = Frekuensi harapan

P = Peluang

A = Kejadian A (hanya lambang suatu kejadian)

n = Banyaknya suatu percobaan

Frekuensi harapan = $\frac{1}{3}\cdot30$ kali = 10