y = $\frac{4}{3}$x + 7

$\Leftrightarrow$ 3y = 4x + 21

$\Leftrightarrow$ 4x + 3y = 21 ... (i)

y = $\frac{2}{3}$x + 5

$\Leftrightarrow$ 3y = 2x + 15

$\Leftrightarrow$ $-$2x + 3y = 15 ... (ii)

Eliminasi persamaan (i) dan (ii)

$-$4x + 3y = 21

$-$2x + 3y = 15  $-$

$-$2x = 6 $\Leftrightarrow$ x = $-$3

Substitusi x = $-$3 ke persamaan (i)

$-$4($-$3) + 3y = 21

$\Leftrightarrow$ 12 + 3y = 21

$\Leftrightarrow$ 3y = 21 $-$ 12

$\Leftrightarrow$ 3y = 9

$\Leftrightarrow$ y = 3

Jadi, titik potong antara garis y = $\frac{4}{3}$x + 7 dan y = $\frac{2}{3}$x + 5 adalah ($-$3,3).