Jika diketahui fungsi g(x)=x+1x, x≠0g\left(x\right)=\frac{x+1}{x},\ x\neq0g(x)=xx+1, x=0 dan h(x)=xx−1, x≠1h\left(x\right)=\frac{x}{x-1},\ x\neq1h(x)=x−1x, x=1, maka (g+h)(x)\left(g+h\right)\left(x\right)(g+h)(x) sama dengan ....
2x2+1x2−x\frac{2x^2+1}{x^2-x}x2−x2x2+1
2x2−1x2+x\frac{2x^2-1}{x^2+x}x2+x2x2−1
1−2x2x2−x\frac{1-2x^2}{x^2-x}x2−x1−2x2
2x2−1x2−x\frac{2x^2-1}{x^2-x}x2−x2x2−1
2x2+1x2+x\frac{2x^2+1}{x^2+x}x2+x2x2+1