Jika garis y=3x−24y=3x-24y=3x−24 memotong lingkaran (x−5)2+(y−1)2=10\left(x-5\right)^2+\left(y-1\right)^2=10(x−5)2+(y−1)2=10 di satu titik, titik potong tersebut adalah ....
(8,−8)\left(8,-8\right)(8,−8)
(0,−8)\left(0,-8\right)(0,−8)
(0,8)\left(0,8\right)(0,8)
(8,0)\left(8,0\right)(8,0)
(−8,0)\left(-8,0\right)(−8,0)