Diketahui a→=(1, 3, 1)\overrightarrow{a}=\left(1,\ 3,\ \ 1\right)a=(1, 3, 1), b→=(2, 3, 5)\overrightarrow{b}=\left(2,\ 3,\ 5\right)b=(2, 3, 5), dan c→=(4, 2, m)\overrightarrow{c}=\left(4,\ 2,\ m\right)c=(4, 2, m). Jika (a→+b→)\left(\overrightarrow{a}+\overrightarrow{b}\right)(a+b) tegak lurus c→\overrightarrow{c}c, maka hasil dari 2a→+b→−2c→2\overrightarrow{a}+\overrightarrow{b}-2\overrightarrow{c}2a+b−2c adalah ....
(−4, 5, 15)\left(-4,\ 5,\ 15\right)(−4, 5, 15)
(4, 5, 15)\left(4,\ 5,\ 15\right)(4, 5, 15)
(12, 5, 15)\left(12,\ 5,\ 15\right)(12, 5, 15)
(−12, 13, −15)\left(-12,\ 13,\ -15\right)(−12, 13, −15)
(12, 13, 15)\left(12,\ 13,\ 15\right)(12, 13, 15)