Diketahui f:x→a+bsinxf:x\rightarrow a+b\sin xf:x→a+bsinx dengan xxx dalam radian. Jika f(π2)=1f\left(\frac{\pi}{2}\right)=1f(2π)=1 dan f(π6)=2f\left(\frac{\pi}{6}\right)=2f(6π)=2, maka f(π3)=....f\left(\frac{\pi}{3}\right)=....f(3π)=....
3−33-\sqrt{3}3−3
2+32+\sqrt{3}2+3
3−23-\sqrt{2}3−2
5+35+\sqrt{3}5+3
1+231+2\sqrt{3}1+23