Latihan Matematika Peminatan Kelas XI Jumlah dan Selisih Dua Sudut
# 2
Pilgan

tanαtan(βγ)1+tanαtan(βγ)\frac{\tan\alpha-\tan\left(\beta-\gamma\right)}{1+\tan\alpha\tan\left(\beta-\gamma\right)} sama dengan ....

A

tan(αβ+γ)\tan\left(\alpha-\beta+\gamma\right)

B

tan(αβγ)\tan\left(\alpha-\beta-\gamma\right)

C

tan(α+β+γ)\tan\left(\alpha+\beta+\gamma\right)

D

tan(α+βγ)\tan\left(\alpha+\beta-\gamma\right)

E

tan(β+γα)\tan\left(\beta+\gamma-\alpha\right)

Pembahasan:

Rumus umum tangen dari selisih dua sudut adalah

tan(αβ)=tanαtanβ1+tanαtanβ\tan\left(\alpha-\beta\right)=\frac{\tan\alpha-\tan\beta}{1+\tan\alpha\tan\beta}

Karena diketahui tanαtan(βγ)1+tanαtan(βγ)\frac{\tan\alpha-\tan\left(\beta-\gamma\right)}{1+\tan\alpha\tan\left(\beta-\gamma\right)} maka

tanαtan(βγ)1+tanαtan(βγ)=tan(α(βγ))\frac{\tan\alpha-\tan\left(\beta-\gamma\right)}{1+\tan\alpha\tan\left(\beta-\gamma\right)}=\tan\left(\alpha-\left(\beta-\gamma\right)\right)

=tan(αβ+γ)=\tan\left(\alpha-\beta+\gamma\right)