Persamaan garis singgung lingkaran x2+y2+6x−4y=0x^2+y^2+6x-4y=0x2+y2+6x−4y=0 x2+y2+12x−8y+36=0x^2+y^2+12x-8y+36=0x2+y2+12x−8y+36=0 di titik (0,0)\left(0,0\right)(0,0) adalah ....
2x−3y=02x-3y=02x−3y=0
3x+2y=03x+2y=03x+2y=0
−2x−3y=0-2x-3y=0−2x−3y=0
2x+3y=02x+3y=02x+3y=0
3x−2y=03x-2y=03x−2y=0