Himpunan penyelesaian dari persamaan nilai mutlak ∣4x−11∣=1\left|4x-11\right|=1∣4x−11∣=1 adalah ....
HP ={52, 3}=\left\{\frac{5}{2},\ 3\right\}={25, 3}
HP ={32, 5}=\left\{\frac{3}{2},\ 5\right\}={23, 5}
HP ={4, 10}=\left\{4,\ 10\right\}={4, 10}
HP ={4, 12}=\left\{4,\ 12\right\}={4, 12}
HP ={10, 12}=\left\{10,\ 12\right\}={10, 12}